Abonner for at downloade
CROSSOVER

Took me a while to recognize that I couldn't simply cross. And then the swap was clear. Good puzzle.

Good one indeed!

Nice puzzle. Found solution 6 / 360 / 6 and after some trial and error the 3 / 0 / 0 one.

I believe this puzzle showcases a genuine bug in the simulation. The obvious solution is to just wire two DX300s to the inputs and outputs and let them do the work, but this inexplicably doesn't work, and for no reason. The whole point of the DX300 is that it acts like a composite adapter for simple I/O and xbus. Saying that a microcontroller is actually needed to get it to spit out the value when spitting out a value is exactly what it's supposed to always be doing is like saying a human being needs to put their hand on the valve of their faucet in order for water to manifest inside it, and that if they leave the valve open and walk away, water will suddenly and magically stop flowing through the faucet. I've heard of solipsism, but this is ridiculous! (and then the seinfeld theme plays)

Anyways this is either unrealistically contrived or a bug.

@raisemanface You need to play the main game until you unlock "conceptSPEC" then you can play custom specs from the workshop.

For humour )) Trys to deal with random on DX300
Almost solved with 4 MC4000X + DX300 (one for input one for output)
MC 4000X all connected to single wire moved between 2 DX300
every has unified code:
```
nop
nop
nop
mov x0 acc
tgt acc 0
+ mov acc x0
+ mov acc x0
+ mov acc x0
slp 1
```
nops - balances input
multiples movs - try to push value to required DX300
it ALMOST working )) - in my case just 5 points of verification was fail. Sad, but challenge to do it not with xors fails )))

How can I use the mod in game? Please help me, thanks!

(I added a screenshot (tagged as a spoiler) in my screenshots if anyone wants to see it)

my solution was ¥3, but I confess I didn't actually plan it, I just slapped down three xor gates in a likely configuration, given the limits of the board size , then connected the outputs and looked at what came out on the verification tab (they were reversed at first)

For the ¥3 solution: 3 xor gate:
- the first one has inA and inB as input, normal output
- top one, inA and 1st xor output as input, normal output to output B
- top one, inB and 1st xor output as input, normal output to output A