Winkelpagina
SHENZHEN I/O
Alles Discussies Screenshots Beeldmateriaal Uitzendingen Video's Workshop Nieuws Gidsen Recensies

SHENZHEN I/O

Winkelpagina
SHENZHEN I/O >  Workshop > Workshop van shigawire
Onvoldoende beoordelingen
DIV 2
Beschrijving Discussies0 Opmerkingen10 Wijzigingen
   
Prijs
Toevoegen aan favorieten
Toegevoegd aan favorieten
Verwijderen uit favorieten
Bestandsgrootte
Geplaatst op
5.415 KB
25 sep 2024 om 5:38
1 wijzigingsnotitie (weergeven)
Gemaakt door
shigawire
Offline
2,233 unieke bezoekers
283 huidige abonnees
4 huidige favorieten

Abonneren om te downloaden
DIV 2

Omschrijving
Just divide a number by 2.

I mean how hard could it be?
10 opmerkingen
< >
Gilgamesh 18 aug om 15:03 
15/4628/33:
https://gtm.steamproxy.vip/sharedfiles/filedetails/?id=3551687440
Moose 6 jun om 21:34 
My solution: https://gtm.steamproxy.vip/sharedfiles/filedetails/?id=3494555087
Moose 6 jun om 21:30 
Got 8/705/19 trivially, I suspect you can use dst to increase throughput but it remains to be seen whether its actually more efficient giventhe pre-processing necessary
NoobDancer100 2 jun om 7:56 
I got 8/70.6k/15 not particually good (especially compared to other people) but easy to understand solution.
Verdammte Heinz 6 nov 2024 om 11:34 
Optimized the low power version for costs to 8 / 705 / 19 . As I could not optimize it further checked the solution from Shigawire, nice one! I only considered taking two lowest digits and multiply those at the same time, but did not think about taking the two higher ones.
Verdammte Heinz 5 nov 2024 om 19:57 
Solved in 6 / 70603 / 12 and 10 / 668 / 18
Scoptlie 14 okt 2024 om 8:33 
@shigawire Oh that's a very clever way to do it! Using the simple IO pin basically for extra storage is something I wish I had considered as I was stuck on eliminating the need for the dat register . I much appreciate your sharing, and thanks for the fun puzzle.
shigawire  [auteur] 11 okt 2024 om 7:21 
@Scoptlie : Mostly it relies on using simple IO to make sharing intermediate values cheap between 2 MC4000s. and that the instructions:
mov <src> acc
dgt 0
can be replaced with
dst 0 <src>
if you know that acc is less than 10

(Screenshot of the 6/631/17 solution )
Scoptlie 9 okt 2024 om 12:05 
This one is driving me mad. The best I can manage after many attempts is 8/705/19 . I'd be curious to see the 6/631/17 solution.
shigawire  [auteur] 26 sep 2024 om 7:45 
So far I have 6/631/17 or 6/50511/13