原贴在这里：http://store.steampowered.com

很久之前看过公式的帖子但是找不到了，于是决定自己做了一下实验并且得出如下的公式。

：
可发酵性糖质量（克）=糖化效率（小数形式，例如80.1%就写为0.801）× 652 × 谷物质量（千克）

时间关系，测试只使用了美式淡色艾尔和优质慕尼黑，其他的种类如果有错误可以在评论区里告知。

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I was told that there is a post of similar things but being unable to find it. So I decided to conduct my own experiments and derived the following formula:

Fermentable sugar mass (grams) = Mash efficiency (in decimal form, e.g., 80.1% is written as 0.801) × 652 × Grain mass (kilograms)

Due to time constraints, the tests were only conducted using American Pale Ale Malt and Premium Munich. If there are inaccuracies with other varieties, please feel free to point them out in the comments.

P.S. I use AI to translate Chinese into English. If it is difficult to understand, you could translate the part of Chinese to your language directly~