Medieval Blacksmith

Medieval Blacksmith

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Ore Weight (speculation)
By BB
For a good design, I weighed the ore. I drew a drawing and compared the weight.

The weight is not perfectly accurate. It's a guess by comparison.

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weighed the ore
My first language is not English. I use a translator.

For a good design, I weighed the ore. I drew a drawing and compared the weight.

The weight is not perfectly accurate. It's a guess by comparison.

It would be useful for someone like me who wants to make each part separate but doesn't like the remaining ore.

Copper : 0.8 Kg
Iron : 0.7 Kg
Silver : 0.95Kg
Gold : 1.75 Kg
Cila : 1.4 Kg
Khanka : 0.55 Kg
Yudhira : 1.2 Kg
Rai : 0.68 Kg
Tamra : 0.48 Kg
Suvarna : 0.65 Kg
Serath : 1.15 Kg
Gaurila : 0.85 Kg
Moraka : 1.65 Kg
Loha : 0.95 Kg

Tip: When you're weighing, pour the molten ore into the blade last. The quality of the ore is lower, but the blade can be taken out without having to fill it 100%.
7 Comments
John Ten 18 Feb @ 11:26pm 
Hexagonal seems to be the standard Fuller to calculate weight, all Fuller Types consume the same amount of ores. I have successfully poured weapons with below 0.005 waste just by eyeing the weight. There are cases of incomplete pour but those are all 98%~99%, imo that's close enough.

Using Total Weight to calculate is also possible:

1 Blade Total Weight = 0.07 ore
1 Heavy Weapon Total Weight = 9 ore
1 Pommel Total Weight = 0.45 ore
1 Guard Total Weight = 0.6 ore

However from a few tests I did some Total Weight seems to have more than two decimal numbers. One such example is 13 Blade0 + 1 Point5, results in 0.79 KG(iron) and 14.29 Total Weight which according to the number above should be 14.29*0.07=1.0003 ore, but this design can be poured by 1 ore with very tiny waste(20 in a row, accumulating waste still below 0.005).

So either my number for Blade Total Weight is a tiny little off, or Point5 is actually 1.285 Total Weight, I think the latter is more likely.
Arch 19 Jan @ 10:01pm 
@Drecknath I decided to try to figure it out. Density of Cila is 15,250. Copper is 8,960. You need 2 Copper and 1 Cila. So add 8,960+8,960+15,250 is 33,170.

These 3 Ores make 3L of Liquid Tamra, same as 3 solid Tamra Ore would also make 3L of Liquid. So, we divide 33,170 by 3 to see the density of just 1L of Liquid. 11,057.

Tamra is 5,384. Less than 1/2 the density of it's components. And going off of what @Pelides said about Density, then this means the weights are not consistent. The combined weight of the ingredients is 3.32 kg for 3L, or 1.10 kg for 1L. And 1L of Tamra is 0.54 kg.

So, it gets lighter... somehow. And I know exactly how. It's because of crazy voodoo black magic. My source for that is I made it the f*ck up.
Drecknath 12 Jan @ 3:18pm 
id be interested to know if the alloys line up weight wise with what it takes to make them
namely Tamra which definitely shouldn't be the lightest based on its make up
Arch 3 Jan @ 6:26pm 
I looked at what @Pelides said about Density, seems like it is right.

Only thing is, it's Density divided by 10,000, not 1,000. I think he knows that, he just missed a 0 when writing is all. With this formula, Iron is 0.787 KG, and my result was 0.788 KG, but I rounded it to 0.76 KG to accommodate for waste, to prevent impartial pours.

All my results are within 0.02 KG to 0.08 KG of the Density method. The Density method will be more accurate, but you'll need to account for incomplete pours yourself. My numbers are a bit lower, but are more useful as a rule-of-thumb cheat-sheet to avoid incomplete pours.

Accuracy vs convenience. Both are better for different things, so go with the one that works best for you.
Arch 3 Jan @ 10:46am 
I did a test days ago. I used a specific blade shape for all of the ores. According to what I found, your results are within about 0.10 KG, with a lot within 0.05 KG. So we're close.

What parts and blade pieces did you use? I would like to replicate your test. I know you are using a translator, so my google sheet might be hard to use. But here it is. You can trey my test if you like.

https://docs.google.com/spreadsheets/d/1zhNtW8exwF-Mrl8L1r_1bD9jPgTlRPdU_1b-aqFophc/edit?usp=sharing
Pelides 3 Jan @ 10:44am 
You can calculate the exact weights of each metal with the density of them given by the book.
From my knowledge one ore will always lead to 0.1L of liquid metal. Since the density is kg/1000L, you can just divide the density by 1000, and you get how much one ore weighs
Fertami 1 Jan @ 9:27am 
thank you for your work and juste to be sure, this is the weight for one nugget ?