So, there are 4 numbers that need to be found (A, B, C, and X(this is depending from person to person, X is determined, pretty much by YOU)), before getting the answer (D(Rounded up)), why its rounded up WILL be explained, so just, hold off on questioning it JUST yet.

• (x₁/2) + (y₁/2) = A
  (1st set of numbers, being of (x₁,y₁), which are determining how many squares are in each board, across and down,)
  
  
• ((x₂/2) + (y₂/2) = B
  (2nd set of numbers being of (x₂,y₂), which are determining how many boards are on the game grid, also across and down.)
  
  
• 0.5X = C
  (Difficulty level, where X is the difficulty you want it at, ultimately deciding what number is multiplied. a quick list of what exactly details difficulty, Easy is around 1, so if you want easy, it can turn into 0.5*1, which equals 0.5. Which, in turn, means medium is 2, hard is 3, so on and so forth, whatever X is, is up to you and how hard you feel you want to make it.)
  
• (C(A) + C)B = D(rounded up)
  (Number of mines to be put in.)
  

To put this fully into perspective of usage, lets use an example of this. Say, I choose these exact settings before punching in the mines count:


So, the first set of numbers, are 4 and 5, making (x₁,y₁)=(4,5). The second set of numbers, are 7 and 4, making (x₂,y₂)=(7,4). With the difficulty level, being a more easier difficulty, so lets say, somewhat easy, aka 1, making X = 1

1. So, first, A, the first set.
   (4/2) + (5/2) = 2 + 2.5 = 4.5
   A = 4.5
2. Then, B, the second set.
   (7/2) + (4/2) = 3.5 + 2 = 5.5
   B = 5.5
3. Then, C, the difficulty value.
   0.5*1 = 0.5
   C = 0.5
4. Finally, D, the mine count.
   (0.5(4.5) + 0.5)5.5 = (2.25 + 0.5)5.5 = 2.75*5.5 = 15.125(rounded up) = 15
   D = 15

So, the "perfect" amount of mines, for the mismatched input of 4, 5, 7, and 4, at easy difficulty, without recursive grid, the best mine count for it, is 15. Why anyone would ever use those settings? IDK, it was just an example.(After testing the example, it actually works out pretty well, huh).