Beltex
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Solutions for all the numbers
By Dimava
I've spent quite a bit of time making a calculator to calculate every possible way to make every possible number. Here it goes.
   
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The Table
Here's the table for every way to make every number up to 9999

https://docs.google.com/spreadsheets/d/1B116t1uSeIIWfBoXmTV6rbPfqeKnMHDccq9xpBYTeyE/edit?usp=sharing

Here's a part if it for the first ten levels (11+ levels are random)
1 = 1
2 = 2 = 1+1
3 = 3 = 1+1+1 = 2+1
5 = 5 = 1+1+1+1+1 = 4+1 = 3+2
10 = 5+5 = (2+2)*2+2 = (1+1+1)*(1+1+1)+1 = 5*2
20 = 4*4+4 = 5*5-5 = ((2+2)*2+2)*2 = ((1+1+1)*(1+1+1)+1)*(1+1) = 5*4 = 5*2*2
25 = 5*5 = 3*3*3-2 = (4+3)*4-3
30 = 5*5+5 = 6*6-6 = 3*3*3+3 = (2+2)*2*2*2-2 = 6*5 = (5+5)*3
29 = 5*5+4 = (5+1)*5-1 = 5*5+2+2 = 3*3*3+2 = (4+4)*4-3
47 = (5+5)*5-3 = 6*6+6+5 = (4-1)*4*4-1
2 Comments
Kwiz 2 Jul, 2024 @ 10:20am 
Really just use a combo of the prime factors for compound numbers, and then for the primes I just subtract or add from a multiple of 6 since all primes after 3 are a multiple of 6, plus or minus 1. this way you kind of grow a toolbox of little shapes you can combine for any number and then put them along feed lines for efficient placement and belt maximization
Vermilisix 3 Feb, 2024 @ 7:17am 
I made a binary adder which has a bunch of powers of 2, and just requires you to convert the number into binary and then replace a few belts to make different numbers