Bio Prototype

Bio Prototype

Not enough ratings
如何高效叠加血珊瑚层数实现最大输出
By 拉文克劳老匹夫
高效率叠加血珊瑚实现最大输出
   
Award
Favorite
Favorited
Unfavorite
实现效果(粘液腺+肠道方案)

通过配置两个肠道,伤害足以秒杀木桩
实现原理(粘液腺+肠道方案)
两个大脑,一个用于生产子嗣,另一个用于输出。

生产子嗣的脑可以随意发挥,只和数量有关,建议只装备1-3个子嗣(百变怪优先),否则电脑会很卡。


输出脑为:翅膀+翅膀/子嗣粘液腺+肠(石头人优先,测试肠比肺输出高)+血珊瑚


假设子嗣的数量为:n

当使用子嗣粘液腺时,血珊瑚的层数为:2*n^2
当使用翅膀粘液腺时,血珊瑚的层数为:2*n*(n+1)

优先使用翅膀粘液腺

当子嗣数量为10时,血珊瑚的层数就有100左右了,如果子嗣数量拉满,血珊瑚的层数会极其恐怖,导致电脑卡顿。
前肢方案1,使用前肢叠加层数(此方法帧率最高)



脑1:输出来源


脑2:生产子嗣,产生最初的异常


原理:

通过 翅膀+粘液腺+脊髓/胃,高层数,高频率的触发前肢,并通过烟花水母神经的高效能触发血珊瑚,且神经有两个节点,可以放置两个血珊瑚,效率加倍。

需要子嗣+肠道/肺,给怪物添加初始异常
前肢方案2,通过爱哭鬼子嗣触发
脑1:输出来源

脑2:爱哭鬼子嗣
用于每日挑战的6器官方案
不是用翅膀而是直接将粘液腺触发体系接在子嗣的后面

胃/脊髓+百变怪/蜜鼠+胃/脊髓+子嗣粘液腺+肠+血珊瑚/毒

根据拿到的器官随机应变

理论层数最高方案(卡顿)
加入骨鲛


4 Comments
gorba 19 May, 2023 @ 6:51pm 
Here is the English translation of your Guide:

----

Efficient stacking of Blood Coral layers for maximum output

What you can expect

[IMAGE 1]

Implementation principles.

You employ dual-brain functionality, one for offspring reproduction, the other for damage output.

Play the offspring-producing brain at will, focused on quantity. I recommended equipping only 1-3 offspring (preferably a Mutant first) to avoid performance issues on your computer.
gorba 19 May, 2023 @ 6:51pm 
[IMAGE 2]

Output brain priority:
Lung of the Gas Toad
Wings of the Fairy
Gland of the Slime Offspring
Intestine of the Camel (with Golem as a higher priority based on tests)
Belly of the Blood Coral.

[IMAGE 3]

For the number of offspring (n):
When using the Gland of the Slime Offspring: Number of Blood Coral layers = 2n^2.
When using the Gland of the Wing Slime: Number of Blood Coral layers = 2n * (n+1).
gorba 19 May, 2023 @ 6:51pm 
Give priority to using the Gland of the Wing Slime.

With ten offspring, there are approximately 100 layers of Blood Coral. Suppose the number of offspring goes beyond ten. In that case, it may result in the number of Blood Coral layers overwhelming your computer.

----

Principle expansion for the 6-organ scheme of daily challenges:

Instead of using Wings, connect the Slime Gland trigger system directly after the Mutant.
gorba 19 May, 2023 @ 6:50pm 
Stomach of Spinal Cord
Offspring of the Mutant or Honey Mouse
Stomach of the Spinal Cord
Gland of the Black Goat
Intestine of the Camel
Belly of the Blood Coral or Poison Bag
Adapt according to randomly obtained organs.

[IMAGE 4]
[IMAGE 5]

The final scheme: Add Tentacle of the Dragon.

[IMAGE 6]
[IMAGE 7]

:lunar2019piginablanket: