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if n == 0:
return 0
if n % 2 == 0 and n > 0:
return f(n/2)
if n % 2 != 0:
return 1 + f(n-1)
k = 0
for i in range(1,1000 + 1):
if f(i) == 3:
k += 1
print(k)