⠀⠀⠀⠀⡀⠤⠠⢆⠀⣠⢔⠚⠦⡢⠤⠐⢒⠦⡄⡀⠀⠀⠀⠀
⠀⠀⢀⠔⠁⠔⠉⠋⠈⠢⠀⠓⠀⠈⢂⠀⢁⡴⢍⠘⡄⠀⠀⠀
⠀⠠⠂⢀⠂⠀⠄⠀⠀⠀⢠⠀⠑⠀⠀⢃⠪⣑⠷⣿⠇⢠⠀⠀
⠔⠁⠀⡄⢀⠼⠀⠀⠀⢸⠀⡄⠀⠃⠀⠈⡤⢄⣶⣏⡅⢘⠀⠀
⢸⠀⠀⡅⡞⠉⠳⣼⣀⣬⢾⣬⡦⡄⠀⠀⠉⠉⠹⠣⠍⡋⠢⡀
⠘⠀⠂⠀⠑⠤⠔⠀⠀⠀⡇⠀⢸⡆⠀⠀⠄⡰⢹⠀⡐⠁⠀⢱
⠀⡇⠡⢄⠀⠀⠈⠒⠓⠀⠈⠀⡱⡀⠀⣸⠔⠀⠀⠚⠀⠀⠀⢸
⠀⠈⢂⣠⣙⡉⠐⠒⠀⠐⠒⠚⢈⠃⠠⠁⠀⠀⠀⡀⠀⠀⢀⡜
⠀⠀⠀⠹⡀⠈⢦⡀⠀⠀⠀⠀⠒⠉⠀⠀⢀⡠⢾⠁⠀⠀⠎⠀
⠀⠀⠀⠀⠱⣀⣸⠈⠉⠹⡀⠀⠀⠀⡖⠉⠉⠀⠹⡀⠀⠀⡇⠀
⠀⠀⠀⠀⠀⠈⠁⠀⠀⠀⠙⠦⣀⣀⡇⠀⠀⠀⠀⠙⠢⠊⠀⠀

+rep ganks freshies

https://tenor.com/view/lvndmark-touching-headset-gif-3099865383256764544

░░█░░░█▀█░█▀▀░█▀█　　 　
▀▀█▀▀░█▀▄░█▀░░█▀▀
░░█░░░▀░▀░▀▀▀░▀░░
⠄⠄⡔⠙⠢⡀⠄⠄⠄⢀⠼⠅⠈⢂
⠄⠄⡌⠄⢰⠉⢙⢗⣲⡖⡋⢐⡺⡄⠈⢆
⠄⡜⠄⢀⠆⢠⣿⣿⣿⣿⢡⢣⢿⡱⡀⠈⠆
⠄⠧⠤⠂⠄⣼⢧⢻⣿⣿⣞⢸⣮⠳⣕⢤⡆
⢺⣿⣿⣶⣦⡇⡌⣰⣍⠚⢿⠄⢩⣧⠉⢷⡇
⠘⣿⣿⣯⡙⣧⢎⢨⣶⣶⣶⣶⢸⣼⡻⡎⡇
⠄⠘⣿⣿⣷⡀⠎⡮⡙⠶⠟⣫⣶⠛⠧⠁
⠄⠄⠘⣿⣿⣿⣦⣤⡀⢿⣿⣿⣿⣄
⠄⠄⠄⠈⢿⣿⣿⣿⣿⣷⣯⣿⣿⣷⣾⣿⣷⡄
⠄⠄⠄⠄⠄⢻⠏⣼⣿⣿⣿⣿⡿⣿⣿⣏⢾⠇
⠄⠄⠄⠄⠄⠈⡼⠿⠿⢿⣿⣦⡝⣿⣿⣿⠷⢀
хорошо⠄⡇⠄⠄⠄⠈⠻⠇⠿⠋⠄⠄⢘⡆
⠄⠄⠄⠄⠄⠄⠱⣀⠄⠄⠄⣀⢼⡀⠄⢀⣀⡜
играет⠄⠄⠄⢸⣉⠉⠉⠄⢀⠈⠉⢏

+rep abuses judgement

Referring to the block diagram, we determine what output the circuit is supposed to
deliver. We see that the input is multiplied by 10^6 and then added to −2.6 V. Hence,
we must have a circuit that has the following input-output relation:
υO = 10^6 υ1 − 2.6 V
Also, the input signal that must be amplified is small, only around 1 μV, and therefore
it needs a large gain to make it usable K = 10^6. The input resistance must be at least
10 kΩ, probably to avoid loading from υ1. The individual OP AMPs cannot have a
gain magnitude exceeding 2000. At some point in the design, the 2.6-V source will
need to be subtracted from the amplified υ1.
Let us analyze each vendor’s submission to see first if the circuits meet the
required specifications.