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[desmos.com]
\left(\frac{x}{7}\right)^2+\left(\frac{y}{3}\right)^2=1\left\{\operatorname{abs}\left(x\right)>3\right\}\left\{y>\frac{\left(-3\sqrt{33}\right)}{7}\right\}
y=\left|\frac{x}{2}\right|-\left(\frac{3\sqrt{33}-7}{112}\right)\cdot x^2-3+\sqrt{1-\left(\left|\left|x\right|-2\right|-1\right)^2}
y=9-8\left|x\right|\left\{0.75<\left|x\right|<1\right\}
y=3\left|x\right|+0.75\ \left\{0.5<\left|x\right|<0.75\right\}
y=2.25\left\{\left|x\right|<0.5\right\}
y=\frac{\left(6\sqrt{10}\right)}{7}+\left(-0.5\left|x\right|+1.5\right)-\frac{3\sqrt{10}}{7}\cdot\sqrt{\left(4-\left(\left|x\right|-1\right)^2\right)\left\{\left|x\right|>1\right\}}