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Een vertaalprobleem melden
SORRY BUT IM DELETING YOU FROM MY LIFE! *clicks delete* LOADING... ███████████
99%. ERROR! It is impossible to delete our friendship. You mean so much to me. Post this to 10 people's walls who you never want to lose. If you get 3 back, you're an amazing friend.
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x ∣= 2(2x 2−1)\Leftright∣cos\alp+sin\alp∣= 2(2cos 2 \alp−1)\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N 2 cos(\alp− 4π )∣=N 2
cos(2\alp)\Right\alp∈[0; 4π]∪[ 3π ;π]1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0; 4π ]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp− 4π )=cos(2\alp)…2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[ 43π ;π]\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp− 4π )=cos(2\alp)…
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~ ~ ~ ~ ~ ~ ~ ~ ~ Repost this if ~ ~ ~ ~ ~ ~ ~ ~ ~
~ ~ ~ ~ you are a beautiful strong black woman ~ ~ ~
~ ~ ~ ~ ~ ~ ~ who don’t need no man ~ ~ ~ ~ ~ ~ ~
╚═════════════════ ೋღ☃ღೋ ════════════════╝