√(-1) 2^3 ∑ π at -273.15°C, it was 0°K

a = 1, b = 1
Therefore
a = b
Square both sides
a^2 = b^2
Subtract (b^2) from both sides
a^2 - b^2 = 0
A square subtracted by another square simplifies to
(a + b)(a - b) = 0
Divide both sides by (a - b)
a + b = 0
Place in the values for (a) and (b)
1 + 1 = 0
Simplifies to
2 = 0
Divide both sides by 2
1 = 0
Add 1 to both sides
1 + 1 = 1
Proving that 1 + 1 = 1